?? - 2015 q3 Answers
3.
g(θ) = 4cos2θ + 2sin2θ
Given that g(θ) = Rcos(2θ - α), where R > 0 and 0° < α < 90°
(a) find the exact value of R and the value of a to 3 decimal places (3)
(b) Hence, solve for -90° < θ < 90°
(a) find the exact value of R and the value of a to 3 decimal places (3)
(b) Hence, solve for -90° < θ < 90°
4cos2θ + 2sin2θ = 1
giving your answers to one decimal place. (5)
(c) Given that k is a constant and the equation
(c) Given that k is a constant and the equation
g(θ) = k
(c) state the range of possible values of k. (2)